TSTP Solution File: NUM636^1 by cvc5---1.0.5

View Problem - Process Solution

%------------------------------------------------------------------------------
% File     : cvc5---1.0.5
% Problem  : NUM636^1 : TPTP v8.1.2. Released v3.7.0.
% Transfm  : none
% Format   : tptp
% Command  : do_cvc5 %s %d

% Computer : n022.cluster.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory   : 8042.1875MB
% OS       : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit  : 300s
% DateTime : Thu Aug 31 10:45:54 EDT 2023

% Result   : Timeout 299.71s 300.19s
% Output   : None 
% Verified : 
% SZS Type : -

% Comments : 
%------------------------------------------------------------------------------
%----No solution output by system
%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.00/0.13  % Problem    : NUM636^1 : TPTP v8.1.2. Released v3.7.0.
% 0.00/0.14  % Command    : do_cvc5 %s %d
% 0.13/0.35  % Computer : n022.cluster.edu
% 0.13/0.35  % Model    : x86_64 x86_64
% 0.13/0.35  % CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.13/0.35  % Memory   : 8042.1875MB
% 0.13/0.35  % OS       : Linux 3.10.0-693.el7.x86_64
% 0.13/0.35  % CPULimit   : 300
% 0.13/0.35  % WCLimit    : 300
% 0.21/0.35  % DateTime   : Fri Aug 25 14:37:25 EDT 2023
% 0.21/0.36  % CPUTime    : 
% 0.21/0.50  %----Proving TH0
% 35.62/35.93  %------------------------------------------------------------------------------
% 35.62/35.93  % File     : NUM636^1 : TPTP v8.1.2. Released v3.7.0.
% 35.62/35.93  % Domain   : Number Theory
% 35.62/35.93  % Problem  : Landau theorem 2
% 35.62/35.93  % Version  : Especial.
% 35.62/35.93  % English  : ~(suc x = x)
% 35.62/35.93  
% 35.62/35.93  % Refs     : [Lan30] Landau (1930), Grundlagen der Analysis
% 35.62/35.93  %          : [vBJ79] van Benthem Jutting (1979), Checking Landau's "Grundla
% 35.62/35.93  %          : [Bro09] Brown (2009), Email to Geoff Sutcliffe
% 35.62/35.93  % Source   : [Bro09]
% 35.62/35.93  % Names    : satz2 [Lan30]
% 35.62/35.93  
% 35.62/35.93  % Status   : Theorem
% 35.62/35.93  %          : Without extensionality : Theorem
% 35.62/35.93  % Rating   : 0.62 v8.1.0, 0.55 v7.5.0, 0.43 v7.4.0, 0.33 v7.2.0, 0.38 v7.0.0, 0.29 v6.4.0, 0.33 v6.3.0, 0.40 v6.2.0, 0.71 v5.5.0, 0.83 v5.4.0, 0.80 v5.2.0, 1.00 v3.7.0
% 35.62/35.93  % Syntax   : Number of formulae    :   13 (   4 unt;   7 typ;   0 def)
% 35.62/35.93  %            Number of atoms       :   10 (   4 equ;   0 cnn)
% 35.62/35.93  %            Maximal formula atoms :    4 (   1 avg)
% 35.62/35.93  %            Number of connectives :   31 (   4   ~;   0   |;   0   &;  21   @)
% 35.62/35.93  %                                         (   0 <=>;   6  =>;   0  <=;   0 <~>)
% 35.62/35.93  %            Maximal formula depth :    9 (   5 avg)
% 35.62/35.93  %            Number of types       :    3 (   2 usr)
% 35.62/35.93  %            Number of type conns  :    7 (   7   >;   0   *;   0   +;   0  <<)
% 35.62/35.93  %            Number of symbols     :    6 (   5 usr;   2 con; 0-2 aty)
% 35.62/35.93  %            Number of variables   :   10 (   0   ^;  10   !;   0   ?;  10   :)
% 35.62/35.93  % SPC      : TH0_THM_EQU_NAR
% 35.62/35.93  
% 35.62/35.93  % Comments : 
% 35.62/35.93  %------------------------------------------------------------------------------
% 35.62/35.93  thf(nat_type,type,
% 35.62/35.93      nat: $tType ).
% 35.62/35.93  
% 35.62/35.93  thf(x,type,
% 35.62/35.93      x: nat ).
% 35.62/35.93  
% 35.62/35.93  thf(suc,type,
% 35.62/35.93      suc: nat > nat ).
% 35.62/35.93  
% 35.62/35.93  thf(set_type,type,
% 35.62/35.93      set: $tType ).
% 35.62/35.93  
% 35.62/35.93  thf(esti,type,
% 35.62/35.93      esti: nat > set > $o ).
% 35.62/35.93  
% 35.62/35.93  thf(setof,type,
% 35.62/35.93      setof: ( nat > $o ) > set ).
% 35.62/35.93  
% 35.62/35.93  thf(estie,axiom,
% 35.62/35.93      ! [Xp: nat > $o,Xs: nat] :
% 35.62/35.93        ( ( esti @ Xs @ ( setof @ Xp ) )
% 35.62/35.93       => ( Xp @ Xs ) ) ).
% 35.62/35.93  
% 35.62/35.93  thf(n_1,type,
% 35.62/35.93      n_1: nat ).
% 35.62/35.93  
% 35.62/35.93  thf(ax5,axiom,
% 35.62/35.93      ! [Xs: set] :
% 35.62/35.93        ( ( esti @ n_1 @ Xs )
% 35.62/35.93       => ( ! [Xx: nat] :
% 35.62/35.93              ( ( esti @ Xx @ Xs )
% 35.62/35.93             => ( esti @ ( suc @ Xx ) @ Xs ) )
% 35.62/35.93         => ! [Xx: nat] : ( esti @ Xx @ Xs ) ) ) ).
% 35.62/35.93  
% 35.62/35.93  thf(estii,axiom,
% 35.62/35.93      ! [Xp: nat > $o,Xs: nat] :
% 35.62/35.93        ( ( Xp @ Xs )
% 35.62/35.93       => ( esti @ Xs @ ( setof @ Xp ) ) ) ).
% 35.62/35.93  
% 35.62/35.93  thf(ax3,axiom,
% 35.62/35.93      ! [Xx: nat] :
% 35.62/35.93        ( ( suc @ Xx )
% 35.62/35.93       != n_1 ) ).
% 35.62/35.93  
% 35.62/35.93  thf(satz1,axiom,
% 35.62/35.93      ! [Xx: nat,Xy: nat] :
% 35.62/35.93        ( ( Xx != Xy )
% 35.62/35.93       => ( ( suc @ Xx )
% 35.62/35.93         != ( suc @ Xy ) ) ) ).
% 35.62/35.93  
% 35.62/35.93  thf(satz2,conjecture,
% 35.62/35.93      ( ( suc @ x )
% 35.62/35.93     != x ) ).
% 35.62/35.93  
% 35.62/35.93  %------------------------------------------------------------------------------
% 35.62/35.93  ------- convert to smt2 : /export/starexec/sandbox/tmp/tmp.sP2IHNJ0bH/cvc5---1.0.5_4382.p...
% 35.62/35.93  (declare-sort $$unsorted 0)
% 35.62/35.93  (declare-sort tptp.nat 0)
% 35.62/35.93  (declare-fun tptp.x () tptp.nat)
% 35.62/35.93  (declare-fun tptp.suc (tptp.nat) tptp.nat)
% 35.62/35.93  (declare-sort tptp.set 0)
% 35.62/35.93  (declare-fun tptp.esti (tptp.nat tptp.set) Bool)
% 35.62/35.93  (declare-fun tptp.setof ((-> tptp.nat Bool)) tptp.set)
% 35.62/35.93  (assert (forall ((Xp (-> tptp.nat Bool)) (Xs tptp.nat)) (=> (@ (@ tptp.esti Xs) (@ tptp.setof Xp)) (@ Xp Xs))))
% 35.62/35.93  (declare-fun tptp.n_1 () tptp.nat)
% 35.62/35.93  (assert (forall ((Xs tptp.set)) (=> (@ (@ tptp.esti tptp.n_1) Xs) (=> (forall ((Xx tptp.nat)) (=> (@ (@ tptp.esti Xx) Xs) (@ (@ tptp.esti (@ tptp.suc Xx)) Xs))) (forall ((Xx tptp.nat)) (@ (@ tptp.esti Xx) Xs))))))
% 35.62/35.93  (assert (forall ((Xp (-> tptp.nat Bool)) (Xs tptp.nat)) (=> (@ Xp Xs) (@ (@ tptp.esti Xs) (@ tptp.setof Xp)))))
% 35.62/35.93  (assert (forall ((Xx tptp.nat)) (not (= (@ tptp.suc Xx) tptp.n_1))))
% 35.62/35.93  (assert (forall ((Xx tptp.nat) (Xy tptp.nat)) (=> (not (= Xx Xy)) (not (= (@ tptp.suc Xx) (@ tptp.suc Xy))))))
% 35.62/35.93  (assert (not (not (= (@ tptp.suc tptp.x) tptp.x))))
% 35.62/35.93  (set-info :filename cvc5---1.0.5_4382)
% 35.62/35.93  (check-sat-assuming ( true ))
% 35.62/35.93  ------- get file name : TPTP file name is NUM636^1
% 35.62/35.93  ------- cvc5-thf : /export/starexec/sandbox/solver/bin/cvc5---1.0.5_4382.smt2...
% 35.62/35.93  --- Run --ho-elim --full-saturate-quant at 10...
% 35.62/35.93  --- Run --ho-elim --no-e-matching --full-saturate-quant at 10...
% 35.62/35.93  --- Run --ho-elim --no-e-matching --enum-inst-sum --full-saturate-quant at 10...
% 35.62/35.93  --- Run --ho-elim --finite-model-find --uf-ss=no-minimal at 5...
% 35.62/35.93  --- Run --no-ho-ma/export/starexec/sandbox/solver/bin/do_THM_THF: line 35:  6441 Alarm clock             ( read result; case "$result" in 
% 299.71/300.19      unsat)
% 299.71/300.19          echo "% SZS status $unsatResult for $tptpfilename"; echo "% SZS output start Proof for $tptpfilename"; cat; echo "% SZS output end Proof for $tptpfilename"; exit 0
% 299.71/300.19      ;;
% 299.71/300.19      sat)
% 299.71/300.19          echo "% SZS status $satResult for $tptpfilename"; cat; exit 0
% 299.71/300.19      ;;
% 299.71/300.19  esac; exit 1 )
% 299.71/300.20  Alarm clock 
% 299.71/300.20  % cvc5---1.0.5 exiting
% 299.71/300.21  % cvc5---1.0.5 exiting
%------------------------------------------------------------------------------